One of the advantages of streams is that you can avoid visiting the whole structure for some operations, like anyMatch or filter+findFirst. However, if you have your own data structure, depending on how you turn it into a stream you may end up visiting it all anyway. What is the right way to turn a custom tree data type into a stream? Consider the following example:
interface Tree{
void forEach(Consumer<Integer> c);
}
final class EmptyTree implements Tree{
public void forEach(Consumer<Integer> c){}
}
interface NonEmptyTree extends Tree{}
record Leave(int label) implements NonEmptyTree{
public void forEach(Consumer<Integer> c){
System.out.println("In forEachLeave "+label);
c.accept(label);
}
}
record Node(NonEmptyTree left, NonEmptyTree right) implements NonEmptyTree{
public void forEach(Consumer<Integer> c){
left.forEach(c); right.forEach(c);
}
}
The two main ways to turn a tree into a stream would be
var sb=Stream.<Integer>builder();
myTree.forEach(sb);
sb.build()
or
Stream.of(myTree).mapMulti(Tree::forEach)
However, both of them call forEach, thus both of them will visit all the tree (and call the prints for all the labels, in this example).
How do you implement a .stream() method in the Tree type so that it would not even visit the whole tree if it is not needed? (because of .anyMatch, for example)