The expression must be of class type, but it has type unsigned char*

Question

I am getting the error "The expression must be of class type, but it has type unsigned char*" in the line "for (int i = 0; i < u.Values.size(); i++)".

What am I doing wrong, and how do I do it correctly?

struct udtBinaryFeatures
{
    unsigned char Values[51];
};


wstring bytefeaturestowstring(udtBinaryFeatures &u)
{
    wstring s = L"";

    for (int i = 0; i < u.Values.size(); i++) 
    {
        if (i > 0)
        {
            s += L"-";
        }
        s += unsignedchartowstring(u[i]);
    }
    return s;
}

If the `Values` data member really does have a fixed size then why not declare it as `std::array Values;` instead? — G.M., Jan 07 '23 at 11:12

score 1 · Accepted Answer · answered Jan 07 '23 at 11:20

1

Your code doesn't work because c-style array don't have methods.

You can use instead: std::array<usigned char, 51> Values

Or add int Size = 51 to your struct and change i < u.Values.size(); to i < u.Size;

answered Jan 07 '23 at 11:20

Darkolin

71
5

The expression must be of class type, but it has type unsigned char*

1 Answers1