I try to write a macro like following: taken from link and I apply same rule to my software whit out success. I notice some difference from C and C++, but I don't understand why, the macro are preprocessor job ! also I notice some difference passing to the macro the values coming from an enumerators.
#include <stdio.h>
#define CONCAT(string) "start"string"end"
int main(void)
{
printf(CONCAT("-hello-"));
return 0;
}
the reported link used to try online the code link to a demo on ideone allow selection of different language C is ok but changing to C++ it doesn't work. Also in my IDE Visual Studio Code (MinGw C++) doesn't work.
My final target is write a macro to parametrize printf() function, for Virtual Console application using some escape codes. I try to add # to the macro concatenation and seems work but in case I pass an enumerator to the macro I have unexpected result. the code is :
#include <stdio.h>
#define def_BLACK_TXT 30
#define def_Light_green_bck 102
#define CSI "\e["
#define concat_csi(a, b) CSI #a ";" #b "m"
#define setTextAndBackgColor(tc, bc) printf(concat_csi(bc, tc))
enum VtColors { RESET_COLOR = 0, BLACK_TXT = 30, Light_green_bck = 102 };
int main(void){
setTextAndBackgColor(30, 102);
printf("\r\n");
setTextAndBackgColor(def_BLACK_TXT , def_Light_green_bck );
printf("\r\n");
setTextAndBackgColor(VtColors::BLACK_TXT , VtColors::Light_green_bck );
printf("\r\n");
printf("\e[102;30m");// <<--- this is the expected result of macro expansion
}
//and the output is : ( in the line 3 seems preprocessor don't resolve enum (the others line are ok) )
[102;30m
[102;30m
[VtColors::Light_green_bck;VtColors::BLACK_TXTm
[102;30m
Obviously I want use enumerators as parameter... (or I will change to #define).
But I'm curious to understand why it happens, and why there is difference in preprocessor changing from C to C++.
If anyone know the solution, many thanks.