In libc++
's implementation of std::function
, if the function object whose type is being erased is small enough to fit inside an SBO then the move operation will copy it, not move it. Yet not every object whose stack memory footprint is small is optimal to be copied. Why copy rather than move?
Consider this example with Clang (using shared_ptr
because it has reference counting):
https://wandbox.org/permlink/9oOhjigTtOt9A8Nt
The semantics in test1()
is identical to that of test3()
where an explicit copy is used. shared_ptr
helps us to see that.
On the other hand, GCC behaves reasonably and predictably:
https://wandbox.org/permlink/bYUDDr0JFMi8Ord6
Both are allowed by the standard. std::function
requires functions to be copyable, a moved-from object is left in unspecified state, and so on. Why do that? The same reasoning may be applied to std::map
: if both the key and value are copyable, then why not make a new copy whenever someone std::move
s a std::map
? That would also be within the standard's requirements.
According to cppreference.com there should be a move and it should be the target.
The example:
#include <iostream>
#include <memory>
#include <functional>
#include <array>
#include <type_traits>
void test1()
{
/// Some small tiny type of resource. Also, `shared_ptr` is used because it has a neat
/// `use_count()` feature that will allow us to see what's going on behind the 'curtains'.
auto foo = std::make_shared<int>(0);
/// Foo is not actually a trivially copyable type. Copying it may incur a huge overhead.
/// Alas, per-C++23 we don't have a pleasure of `move_only_function`,
/// so 'staying standard' we're stuck with the std::function.
static_assert(!std::is_trivially_copyable_v<std::decay_t<decltype(foo)>>);
static_assert(!std::is_trivially_copy_constructible_v<std::decay_t<decltype(foo)>>);
std::cout << std::endl;
std::cout << "Test 1: tiny function that is probably stored in SBO" << std::endl;
std::cout << "Ref count: " << foo.use_count() << std::endl;
std::function<void()> f = [foo] {
/// Do stuff.
};
std::cout << "Ref count: " << foo.use_count() << std::endl;
{
auto g = std::move(f);
/// Underlying, type-erased data is actually copied not moved
std::cout << "Ref count: " << foo.use_count() << std::endl;
}
std::cout << "Ref count: " << foo.use_count() << std::endl;
}
void test2()
{
auto foo = std::make_shared<int>(0);
std::cout << std::endl;
std::cout << "Test 2: non-tiny function that doesn't fit in SBO" << std::endl;
std::cout << "Ref count: " << foo.use_count() << std::endl;
std::function<void()> f = [foo, bar = std::array<char, 1024>()] {
(void)bar;
/// Do stuff.
};
std::cout << "Ref count: " << foo.use_count() << std::endl;
{
auto g = std::move(f);
std::cout << "Ref count: " << foo.use_count() << std::endl;
}
std::cout << "Ref count: " << foo.use_count() << std::endl;
}
void test3()
{
auto foo = std::make_shared<int>(0);
std::cout << std::endl;
std::cout << "Test 3: tiny function but using a copy" << std::endl;
std::cout << "Ref count: " << foo.use_count() << std::endl;
std::function<void()> f = [foo] {
/// Do stuff.
};
std::cout << "Ref count: " << foo.use_count() << std::endl;
{
auto g = f;
std::cout << "Ref count: " << foo.use_count() << std::endl;
}
std::cout << "Ref count: " << foo.use_count() << std::endl;
}
int main()
{
test1();
test2();
test3();
return 0;
}