I wanted to make a program that would output a image fron the internet by a link to the screen, but the image either appears as a cropped strip, or does not appear at all. I will be very grateful for you help code
package com.example.myapplication2;
import androidx.appcompat.app.AppCompatActivity;
import android.graphics.Bitmap;
import android.graphics.BitmapFactory;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.ImageView;
import android.widget.TextView;
import android.widget.Toast;
import java.io.IOException;
import java.io.InputStream;
import java.net.MalformedURLException;
import java.net.URL;
public class MainActivity extends AppCompatActivity {
private EditText s;
private TextView d;
private Button button1;
private URL link;
private InputStream j;
private Bitmap bitmap;
private ImageView image4;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
d = findViewById(R.id.textView12);
s = findViewById(R.id.editText1);
button1 = findViewById(R.id.button1);
image4 = findViewById(R.id.imageView3);
}
@Override
protected void onResume() {
super.onResume();
}
public void onClickStart(View view){
new Thread(new Runnable() {
@Override
public void run() {
try {
link = new URL(s.getText().toString());
try {
j = (InputStream)link.getContent();
}
catch (IOException e){
d.setText("fail");
}
}
catch (MalformedURLException e){
d.setText("fail");
}
runOnUiThread(new Runnable() {
@Override
public void run() {
bitmap = BitmapFactory.decodeStream(j);
image4.setImageBitmap(bitmap);
}
});
}
}).start();
}
}
enter image description here enter image description here
It is possible in incorrect handling of the permission or file type, I would appreciate your help