I want to find the element of a given index and the element near to it from a large python list like this:
list = ['askdjh', 'afgld', 'asf' ,'asd', '623gfash', 'fhd', 'hfdjs']
And I chose 'asd' :
number = 4
item near it = 623gfash
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Jamiu S.
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Marius Radulescu
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Please, show the code you have tried, so we can help you. – Ignatius Reilly Jan 15 '23 at 15:18
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What's should happen if the target is the last number, `'hfdjs'` in your example? – Ignatius Reilly Jan 15 '23 at 15:19
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I think it should print out of near objects but still to print its pos – Marius Radulescu Jan 15 '23 at 15:20
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1What do you need that position for? Notice that python indexes from 0, not from 1. So, despite `'asd'` is the 4th item, it's index is 3. – Ignatius Reilly Jan 15 '23 at 15:20
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Yes, but which one would be the "near object" of the last item? In your example, the near object is the next one. There's no _next one_ after the last one. – Ignatius Reilly Jan 15 '23 at 15:21
2 Answers
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Use
pos = my_list.index('asd')
nearest = my_list[pos + 1]
Note pos is 3 for the 4th element as Python is 0- based. Note avoid using list for variables as this name has a special meaning in Python.
user19077881
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It is worth adding a check to see if this element is the last one, so as not to go beyond the list: if pos+1
– stukituk Jan 15 '23 at 15:12
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Try below
ind=ls.index("asd")
if ind<len(ls)-1:
print(f"{ind}",ls.__getitem__(ind+1))
else:
print(f"{ind}", ls.__getitem__(ind - 1))
ind, will give you the index of the chosen obj, and using that index only you can fetch closest obj by adding or subtracting 1 from the "ind"
Devesh Joshi
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