Ignore comma within nested parentheses for a Regex match

Question

I have the following Regex /[^,\s]+(?:\s+\([^)]*\))?/g that allows me to match elements separated by a comma while ignoring the commas inside ()

Having this:

a,b,c (aaa, bbb, ccc),d

I get this

a
b
c (aaa, bbb, ccc)
d

Now, I want to upgrade it to consider another level of parentheses. I don't want to consider any level (I know recursive is not possible) but only 2 level max.

Having this:

a,(b, b),c (aaa, (bbb, cccc, ddd)),d

I need to get

a
(b, b)
c (aaa, (bbb, cccc, ddd))
d

I am using https://regex101.com/ for testing if that helps.

Try `(?:\([^()]*(?:\([^()]*\)[^()]*)*\)|[^,])+`. See https://regex101.com/r/zJtxNM/1 — Wiktor Stribiżew, Jan 16 '23 at 14:22
@WiktorStribiżew seems to work fine :) but how to make it works inside the match() of Javascript? I am not getting the same result there :s — Temani Afif, Jan 16 '23 at 14:30
Doesn't `text.match(/(?:\([^()]*(?:\([^()]*\)[^()]*)*\)|[^,])+/g)` work? — Wiktor Stribiżew, Jan 16 '23 at 14:31
@WiktorStribiżew yes yes, nevermind. Forgot the `g` at the end -.-. You can make it an answer if you want :) — Temani Afif, Jan 16 '23 at 14:34

score 2 · Accepted Answer · answered Jan 16 '23 at 14:38

You can use

const matches = text.match(/(?:\([^()]*(?:\([^()]*\)[^()]*)*\)|[^,])+/g);

See the regex demo.

The regex matches one or more repetitions of

\([^()]*(?:\([^()]*\)[^()]*)*\) - a ( + zero or more chars other than parentheses + zero or more repetitions of a substring between parentheses followed with zero or more chars other than parentheses + a ) char (substring between max two-level nested parentheses)
| - or
[^,] - a char other than a comma.

Ignore comma within nested parentheses for a Regex match

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