javascript switch with multiple variables in case

Question

This feels like a silly question but I can't get it to work:

I am building an event handler that I want to trigger two different outcomes if the user presses "enter" or "shift Enter"

I have this code


         switch(e){
            case (e.keyCode == 13 && !e.shiftKey):
                console.log("Enter")
                break;
            case (e.keyCode == 13 && e.shiftKey):
                console.log("Enter&Shift")
                break;
            default:
                console.log(`Sorry, we are out of it.`);
        }

but something is not working because it always go to default...despite the fact that e.keyValue is actually 13 and e.shiftKey is true...so I am passing the event correctly.

It's the switch that is wrongly built.

score 2 · Accepted Answer · answered Jan 16 '23 at 15:26

2

You shouldn't use a switch statement for this, but regular if and else statements.

if (e.keyCode == 13 && !e.shiftKey) {
    console.log("Enter");
} else if (e.keyCode == 13 && e.shiftKey) {
    console.log("Enter&Shift");
} else {
    console.log(`Sorry, we are out of it.`);
}

answered Jan 16 '23 at 15:26

Unmitigated

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This is a fairly common duplicate question. – T.J. Crowder Jan 16 '23 at 15:28
Thanks. I understand how to do this with if...but to be honest that's not what I asked. I was trying to do so using switch and my question was on why was I failing... – giaggi Jan 16 '23 at 15:48
@giaggi Well you would need to use `switch(true)`, which is not a good use of `switch`. – Unmitigated Jan 16 '23 at 15:48
1

@giaggi - Which reading the answers to the linked previous versions of this question would tell you. – T.J. Crowder Jan 16 '23 at 15:52
Thanks! Now it's all clear! Appreaciate the help! – giaggi Jan 16 '23 at 16:00

javascript switch with multiple variables in case

1 Answers1