Is there a way to show name from variable as parameter in php

Question

I would like to get the name (not the value) of a paramter. In the given case it should be $param.

function testfunc($param = 'i do not want this..', $array = array()) {
    $args = func_get_args();
    var_dump($args);
    echo $param; 
}

If I call the testfunc like this:

testfunc($testString,$testArray);

the result should be "$testString" ,"$testArray"

Is there a way in PHP?

The duplicates return the parameter names declared in the function signature. https://3v4l.org/oY24M If you want to ignore the signature declarations and access the passed in variable names, why not pass them in as single quote wrapped strings? `'$testString'` and `'$testArray'`? What are you trying to achieve with this task? — mickmackusa, Jan 23 '23 at 19:59

score 3 · Answer 1 · answered Jan 16 '23 at 17:15

3

Use reflection

$myParams =  array_map( function( $parameter ) { return $parameter->name; }, (new ReflectionFunction(__FUNCTION__))->getParameters() );

Thanks

answered Jan 16 '23 at 17:15

AVRajan

1

Please flag duplicate questions instead of answering them. – mickmackusa Jan 17 '23 at 01:20
1

[Very similar post](https://stackoverflow.com/a/34175664/2943403) – mickmackusa Jan 17 '23 at 01:21
I edited my question. not func_get_args(); not get_defined_vars(); not new ReflectionFunction; helps – hamburger Jan 17 '23 at 12:02
thx @mickmackusa the thing is that i do not wont the string parameter i wont: testString – hamburger Jan 23 '23 at 13:14

1 Answers1