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I have a list of datetime object (let say datetime_obj) Now I want only its time part .

datetime_obj[0] = 22-Jun-23 13:32:00

I'm trying this :

time = [datetime.datetime.strptime(str(i)[11:], '%H:%M:%S') for I in datetime_obj]

But when I am printing time it showing 01-Jan-1900 13:32:00

Basically it is attaching a random date. what should I do?

FObersteiner
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Devendra Yadav
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  • Does this answer your question? [Easiest way to combine date and time strings to single datetime object using Python](https://stackoverflow.com/questions/9578906/easiest-way-to-combine-date-and-time-strings-to-single-datetime-object-using-pyt) – FObersteiner Jan 21 '23 at 10:20

1 Answers1

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You can directly call the ".strftime("%H:%M:%S")" method on your datetime object. This way you can avoid the list comprehension method you were using.

For example, the one-liner

print(datetime.datetime.now().strftime("%H:%M:%S"))

gives you the actual time printed in the format that you need from the datetime object datetime_obj=datetime.datetime.now()

If you need the values instead, you could access to the .hour, .minute and .second properties of datetime_obj.

Domenico
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