How to convert string into list of integers in Python?

Question

I have this:

  "1,2,3,4,5,6,7,8,9,0"

And need this:

  [1,2,3,4,5,6,7,8,9,0]

Everything I search for has the example where the string is a list of strings like this:

  "'1','2','3'..."

those solutions do not work for the conversion I need.

What do I need to do? I need the easiest solution to understand for a beginner.

A one line solution: `list(map(int,s.split(',')))`, where `s` is your string variable — Ben Grossmann, Feb 01 '23 at 18:53

score 1 · Answer 1 · answered Feb 01 '23 at 18:53

1

You can use str.split to get a list, then use a list comprehension to convert each element to int.

s = "1,2,3,4,5,6,7,8,9,0"
l = [int(x) for x in s.split(",")]
print(l)

answered Feb 01 '23 at 18:53

Unmitigated

score 1 · Accepted Answer · answered Feb 01 '23 at 18:55

1

You could use a mapping to convert each element to an integer, and convert the map to a list:

s = "1,2,3,4,5,6,7,8,9,0"
l = list(map(int, s.split(',')))
print(l)

answered Feb 01 '23 at 18:55

Lexpj

1

I like this one. It's easy to understand and explain to others. (for me) – user3486773 Feb 01 '23 at 18:57

score 0 · Answer 3 · answered Feb 01 '23 at 18:57

0

You can just call int("5") and you get 5 like a int.

In your case you can try list comprehension expression

a = "1,2,3,4,5,6,7,8,9,0"
b = [int(i) for i in a.split(',')]
print(b)
>> 1,2,3,4,5,6,7,8,9,0

answered Feb 01 '23 at 18:57

Anton Manevskiy

3 Answers3