python selenium 4.8.0 -

Question

So i have a log-in script and i just try find element by class on newest version of selenium (4.8.0)

code:

button = browser.find_element(By.CLASS_NAME, 'just class name')

AND this code not working.

my stuff:

this is how the documentation searches for elements - By.CLASS_NAME, By.ID, etc...

tried other variations of the code like find_element_by_ID and etc, installed an additional library for the selenium (I do not remember the name).

Please provide at least the relevant html or url to your site. — kaliiiiiiiii, Feb 04 '23 at 10:24

score 1 · Answer 1 · edited Feb 05 '23 at 17:19

1

CSS classes and IDs never contain spaces. You can check if this class exists in the DOM by typing in browser console:

document.querySelectorAll('.class_name')

change class_name with class name you looking for. If the element has multiple classes each is prefixed by a period (.).

document.querySelectorAll('.class_name1.class_name2')

edited Feb 05 '23 at 17:19

JeffC

answered Feb 04 '23 at 10:48

adamczarnecki

1

The shortcut to `document.querySelectorAll()` in the browser console is `$$()`, e.g. `$$('.class_name')`. It will save you some typing. `$x()` will do the same thing but for XPath. – JeffC Feb 05 '23 at 17:07
Also, `.querySelectorAll()` takes CSS selectors so a space means descendant, not class. Each class must be prefixed with a period (.). – JeffC Feb 05 '23 at 17:20

score 1 · Accepted Answer · answered Feb 04 '23 at 12:24

By.CLASS_NAME accepts only single classname as an argument. So you can't pass multiple classnames.

Solution

You can use either of the following locator strategies:

Using the classname just:

button = browser.find_element(By.CLASS_NAME, 'just')

Using the classname class:

button = browser.find_element(By.CLASS_NAME, 'class')

Using the classname name:

button = browser.find_element(By.CLASS_NAME, 'name')

As an alternative, you can also use a css_selector as follows:

button = browser.find_element(By.CSS_SELECTOR, ".just.class.name")