python findall null

Question

I'm generating a bot that should receive telegram messages and forward them to another group after applying regex to the received message.

Regex tested in PHP and sites around the web, in theory it should work.

regex = r"⏰ Timeframe M5((\s+(.*)\s+){1,})⏰ Timeframe M15"
text_example = '''⏰ Timeframe M5


04:05 - EURUSD - PUT
05:15 - EURJPY - PUT
06:35 - EURGBP - PUT
07:10 - EURUSD - PUT
08:15 - EURJPY - PUT

⏰ Timeframe M15

06:35 - EURGBP - PUT
07:10 - EURUSD - PUT
08:15 - EURJPY - PUT '''

reg = re.findall(regex, example_text)
print(reg)

return me [ ]

I've run out of attempts..

I've used regex in other situations and had no problems, in this one I don't know why it works

I've pasted your regex and example input in https://regex101.com and it doesn't work. — Samathingamajig, Feb 06 '23 at 15:56
Which part do you expect to be captured by the capturing-group? — MSpiller, Feb 06 '23 at 16:01
@M.Spiller everything between Timeframe M5 and ⏰ Timeframe M15 — Djoi Patrick Santos de Souza, Feb 06 '23 at 16:57
The difference between the regex behind https://regex101.com/r/gvulvK/3 and the code you have pasted above is the _multiline_ mode. Try changing your call to `findall` to `re.findall(regex, example_text, re.MULTILINE)` — MSpiller, Feb 07 '23 at 09:10

score 0 · Accepted Answer · answered Feb 06 '23 at 19:49

The pattern does not work for the example data because you are repeating 1 or more leading AND trailing whitespace characters after .*. This will not match if you have 2 consecutive lines without for example extra spaces at the end that you do seem to have in this regex example https://regex101.com/r/gvulvK/3

Note that the name of the initial variable is text_example

What you might do is match the start and the end of the pattern, and in between match all lines that do not start with for example the ⏰

⏰ Timeframe M5\s*((?:\n(?!⏰).*)+)\n⏰ Timeframe M15\b

See this regex101 demo and this regex101 demo

import re

regex = r"⏰ Timeframe M5\s*((?:\n(?!⏰).*)+)\n⏰ Timeframe M15\b"
text_example = '''⏰ Timeframe M5


04:05 - EURUSD - PUT
05:15 - EURJPY - PUT
06:35 - EURGBP - PUT
07:10 - EURUSD - PUT
08:15 - EURJPY - PUT

⏰ Timeframe M15

06:35 - EURGBP - PUT
07:10 - EURUSD - PUT
08:15 - EURJPY - PUT '''

reg = re.findall(regex, text_example)
print(reg)

Output

['\n04:05 - EURUSD - PUT\n05:15 - EURJPY - PUT\n06:35 - EURGBP - PUT\n07:10 - EURUSD - PUT\n08:15 - EURJPY - PUT\n']

score -1 · Answer 2 · answered Feb 06 '23 at 15:58

-1

If you slightly change your regex and also run it in dot all mode, it should work:

regex = r'⏰ Timeframe M5.*?⏰ Timeframe M15'
matches = re.findall(regex, text_example, flags=re.S)
print(matches)

This prints:

⏰ Timeframe M5


04:05 - EURUSD - PUT
05:15 - EURJPY - PUT
06:35 - EURGBP - PUT
07:10 - EURUSD - PUT
08:15 - EURJPY - PUT

⏰ Timeframe M15

answered Feb 06 '23 at 15:58

Tim Biegeleisen

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no feedback has worked yet – Djoi Patrick Santos de Souza Feb 06 '23 at 17:00

python findall null

2 Answers2