Subtracting asctime from time module to get hours minutes and seconds in python

Question

How can I subtract end - start to get hours minutes and seconds of time completion in Python?

I have some pseudocode here, I want to convert the print statement to what I said above.

start = time.asctime(time.localtime(time.time()))

< some code here>

end = time.asctime(time.localtime(time.time()))

print(end - start)

Keep your `start` and `end` variable in epoch time and only a the end do something like `time.strftime("%H:%M:%S",time.localtime(end-start))` — obchardon, Feb 06 '23 at 16:46
I would use `time.gmtime` here to avoid timezone offsets being included. — Steven Summers, Feb 06 '23 at 16:55
Does this answer your question? [How to measure time taken between lines of code in python?](https://stackoverflow.com/questions/14452145/how-to-measure-time-taken-between-lines-of-code-in-python) — Abdul Aziz Barkat, Feb 06 '23 at 16:57

score 1 · Answer 1 · answered Feb 06 '23 at 16:54

a solution using datetime

You can use the datetime module in Python to subtract two datetime objects and obtain a timedelta object that represents the duration between the two times. The timedelta object can be further used to extract hours, minutes, and seconds by accessing its attributes total_seconds(), seconds, minutes, hours, and days. Here is an example:

import datetime  

start = datetime.datetime.now()
end = datetime.datetime.now()

duration = end - start

hours, remainder = divmod(duration.total_seconds(), 3600)
minutes, seconds = divmod(remainder, 60)

Subtracting asctime from time module to get hours minutes and seconds in python

1 Answers1