How do I create a zod object with dynamic keys?

Question

We can create Zod object that validates an object against the keys that are defined in the schema, but I only want to validate if the key is a string not if the key == something

In typescript we can achieve this by using

Record<string, string>;

But in zod, I tried this one

const data = z.object({
  [z.string()]: z.string(),
});

But it's not working

score 29 · Accepted Answer · answered Feb 07 '23 at 14:15

29

You're looking for z.record which can be used like:

const data = z.record(z.string(), z.string());

answered Feb 07 '23 at 14:15

Souperman

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It seems that we can also omit the 2nd. parameter: `const data = z.record(z.string());` – developer033 Jul 19 '23 at 21:41
To be 100% accurate: You can skip the first argument. But in this case it still ends up being `const data = z.record(z.string());`. – Bjørn Bråthen Aug 21 '23 at 13:42

How do I create a zod object with dynamic keys?

1 Answers1