l = [10,10,10,10]
for x in l:
l.remove(x)
print(l)
Im getting the output as [10,10]
But not able to understand why
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Mathias R. Jessen
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What are you trying to do? Please also format your question correctly to display your code in a code block. – D Malan Feb 16 '23 at 13:56
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You're iterating over a list and modifying it. You're skipping every second index. – B Remmelzwaal Feb 16 '23 at 13:56
1 Answers
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l = [1, 2, 3, 4]
for i,e in enumerate(l):
l.remove(e)
print(i)
print(l)
Output: [2, 4]
First iteration, frst element is removing, then the list is [2, 3, 4]. Second iteration, you remove the second element of the new list ([2, 3, 4]), so you remove the 3, and 4 become the 2nd element. After that, you can't remove the third element because it does'nt exist.
If you run my code, you'll see that only 2 iterations are done.
If you want to delete items without modify index of the next, you can start by the end of the list as above.
l = [1, 2, 3, 4]
for i in range(len(l) - 1, - 1, -1):
l.remove(l[i])
print(i)
print(l)
This time the loop is running 4 times and the final list is empty.
Berni
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