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I have tried multiple ways like splitting each value and the rearranging. and the code seems too lengthy can someone help me to write it in a shorter way.

time = "28/01/2023 13:17:58" I split it to

lis = [28,01,2023]
lis2 = [13,17,58]

then rearranged it to

t = 28/01/2023 13:17:58

can someone tell me how I can use datetime to simplify this?

Goutham
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    Did you look at [`datetime.strptime()`](https://docs.python.org/3/library/datetime.html#datetime.datetime.strptime)? – Delgan Feb 16 '23 at 16:21
  • @Delgan tried that but it was throwing error while trying to convert directly from string to datetime – Goutham Feb 16 '23 at 16:23
  • Parsing directive `"%d/%m/%Y %H:%M:%S"` ?! – FObersteiner Feb 16 '23 at 16:37
  • Does this answer your question? [Convert string "Jun 1 2005 1:33PM" into datetime](https://stackoverflow.com/questions/466345/convert-string-jun-1-2005-133pm-into-datetime) – FObersteiner Feb 16 '23 at 16:40

2 Answers2

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from datetime import datetime

time = "28/01/2023 13:17:58"
datetime_obj = datetime.strptime(time, "%d/%m/%Y %H:%M:%S")
print(datetime_obj) # 2023-01-28 13:17:58
shivankgtm
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date = "28/01/2023 13:17:58"

datetime.datetime.strptime(date, '%d/%m/%Y %H:%M:%S')

Output = datetime.datetime(2023, 1, 28, 13, 17, 58)

Abhishek Kumar
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