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I am trying to find the logarithmic value for ax where a <= 9999 and x <= 9999, e.g. 9999 I got as 656.3063053878814, i.e. I got only 13 digits after the decimal point. I would like to know if I can get at least 50 to 99 digits after the decimal point.
Thanks in advance.

I copied the code from one of the member from this group written in Java and used it. No idea if it's OK to paste here, hence asking for a simpler code in Java, please.

Abra
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user3579609
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  • `System.out.println(java.math.BigInteger.valueOf(99).pow(99));` – Elliott Frisch Feb 24 '23 at 01:08
  • If that code comes from Stack Overflow, it’s perfectly OK to post it here. You may additionally link to the post you took it from for credit. – Ole V.V. Feb 24 '23 at 03:18
  • Convert to a `BigDecimal` using `new BigDecimal(BigInteger.valueOf(99).pow(99))` and then apply [Logarithm of a BigDecimal](https://stackoverflow.com/questions/739532/logarithm-of-a-bigdecimal). There isn’t any method built into Java, so it’s necessarily as manual as that. Don’t know whether that was the post you were referring to. – Ole V.V. Feb 24 '23 at 03:25
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    The log (a\*\*x) = x \* log(a). Other than that see the comment by @OleV.V. – President James K. Polk Feb 24 '23 at 14:34

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