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def string_splosion(str):
    result = ""
                                                   
    for i in range(len(str)):
        result = result + str[:i + 1]
    return result

I got this answer from codingBat. Can someone explain this code to me? I am having trouble understanding what the :i + 1 does in str{0:i + 1] code. Thanks

Tried multitiude of things to solve the problem. But keep getting it wrong.

  • print(string_splosion('Code')) print(string_splosion('abc')) This is what I was trying to print out print(string_splosion('ab')) – Hamza Khatib Mar 06 '23 at 03:21
  • "Can someone explain this code to me?" No, because [there is no way that we can know what you need to know, or why you don't already understand it](https://meta.stackoverflow.com/questions/253894). Start by trying to check carefully what the code does, step by step. You should have a clear expectation in mind for what each part of the code does; if not, then pick one specific thing where you don't have that expectation, [try to look for existing information](https://meta.stackoverflow.com/questions/261592) (for example, by following a Python tutorial), and then ask **specifically**. – Karl Knechtel Mar 06 '23 at 03:50
  • (The same applies to your previous question, BTW.) – Karl Knechtel Mar 06 '23 at 03:53
  • What previous question? – Hamza Khatib Mar 06 '23 at 03:58
  • The [previous one that you asked on Stack Overflow](https://stackoverflow.com/questions/75583101/explaining-how-to-remove-duplicates). – Karl Knechtel Mar 06 '23 at 04:00
  • Ok. Understood on being more specific – Hamza Khatib Mar 06 '23 at 04:02
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    Please let us know if you are asking the following question: 'I do not understand the role of the colon ":", in "str[ :i + 1]" which appears in the code below, which I got from codingBat. I would appreciate it if someone could explain what that colon does and/or direct me to some URL(s) where I could learn more about it.' – Marc B. Hankin Mar 06 '23 at 20:55

1 Answers1

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If you simply print i and result in the for loop, you should able to understand the main idea. Also, you could rewrite str[:i + 1] with str[0:i+1] which is probably more self-explanatory.

Here is what you should get if you print the i and result:

0 c
1 cco
2 ccocod
3 ccocodcode

Focus on the "added" part for each step. You see that it starts with only 1 character, since id adds str[0:1] in the first step. If you don't know about slice notation, check this thread: Understanding slicing

I hope it's helpful.

Atalay K.
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