How to swap values of args in JS

Asked Mar 06 '23 at 22:12

Active Mar 06 '23 at 22:14

Viewed 15 times

I tried to swap the values of args in JS Function. My function looks like this:

function swapValues(x,y){ 
return (y,x);}

And I call this function as below:

console.log(swapValues(5,10))

I expected for the output to give me (10,5) but it's 5
So, can you please let me know why it's 5 there?

edited Mar 06 '23 at 22:14

jonrsharpe

asked Mar 06 '23 at 22:12

2

Because that's the [comma operator](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Comma_Operator). – jonrsharpe Mar 06 '23 at 22:14
that means I can not return 2 values from a function while using comma? – Mar 06 '23 at 22:15
4

A function can only return one value. That value can be e.g. an _array_, though. – jonrsharpe Mar 06 '23 at 22:16
`return [y, x]`, not `return (y, x)`. – user229044 Mar 06 '23 at 22:16
okay, got it :D – Mar 06 '23 at 22:17

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