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I'm running the following snippet. For some reason, which I don't get, a "b" appears in the path when stating the location of a file.

# %% Definitions

path_root = normpath(r'G:\\Dropbox\\temp\\')
path_start = normpath(r'G:\\Dropbox\\temp\\worklayers\\')
path_temp = normpath(r'G:\\Dropbox\\temp\\templayers\\')
path_temp2 = normpath(r'G:\\Dropbox\\temp\\temp2layers\\')
path_end = normpath(r'G:\\Dropbox\\temp\\resultlayers\\')
path_doc = normpath(r'G:\\Dropbox\\Documents\\')

directory = os.fsencode(path_start)

df = pd.read_csv(path_doc+'\\DEM_masterfile.csv')

slope_list = [4, 4.9, 5.9, 7.1, 8.2, 10, 11.8, 13.8, 15.7, 17.9, 20.6, 25]
aspect_list_1 = [[0, 15], [15,30], [30, 45], [45, 60], [60, 75], [75, 90], [90, 105], [105, 120], [120, 135], [135, 150], [150, 165], [165, 180]]
aspect_list_2 = [[180, 195], [195, 210], [210, 225], [225, 240], [240, 255], [255, 270], [270, 285], [285, 300], [300, 315], [315, 330], [330, 345], [345, 360]]

# %% Generating the slope and aspect vector files from the DEM raster

for number in os.listdir(directory):
    
    processing.run("native:slope", {'INPUT':path_start+'\\'+str(number),'Z_FACTOR':1,'OUTPUT':path_temp+'\\'+'slope_'+str(number)})
    processing.run("native:aspect", {'INPUT':path_start+'\\'+str(number),'Z_FACTOR':1,'OUTPUT':path_temp+'\\'+'aspect_'+str(number)})

When running this the following error appears Could not load source layer for INPUT: G:\Dropbox\temp\worklayers\b'hej0.tif' not found

Where is that b in the error message coming from?? G:\Dropbox\temp\worklayers\b'hej0.tif'

Tobias Bowley
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  • Does this answer your question? [What does a b prefix before a python string mean?](https://stackoverflow.com/questions/2592764/what-does-a-b-prefix-before-a-python-string-mean) – Adrian Mole Mar 07 '23 at 14:43

1 Answers1

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os.fsencode(path_start) returns an instance of bytes. Then os.listdir(directory) returns a list of bytes because you gave bytes as its argument.

The b'...' is the result of calling str(...) on an instance of bytes. I'm not sure what the reason was for using os.fsencode in this code and ending up with bytes.

To convert a bytes to a string, you could use decode() or os.fsdecode, the reverse of os.fsencode.

khelwood
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  • The reason I use {os.fsencode} is because I want to list the files in a path. I guess there's two options; turn them into strings or use another method of listing the files in that path. Thanks for clearing it out! – Tobias Bowley Mar 07 '23 at 19:31