Regex for extractig dots

Question

I almost lost 4 hours triying to make it work and i give up.

Given the next string:

adsdasd.sdfdsfsdf.f43fvev.ASCSDF.sfgsdfssdf.yaml

I want a regex, posix possible to:

substitute all the . for /
except the .yaml that it should be remain so.

So, this must be the final string:

adsdasd/sdfdsfsdf/f43fvev/ASCSDF/sfgsdfssdf.yaml

I tried with:

:(

With `I want a regex, posix` Do you mean you want a POSIX BRE or ERE regex? What is the tool or language that you are using — The fourth bird, Mar 09 '23 at 21:46
It says it is Perl but....it is not, it is perl but under GO. So almost all lookahead doesnt work — PsySkeletor, Mar 13 '23 at 16:53

score 2 · Answer 1 · answered Mar 09 '23 at 16:43

2

This will help to get all the dots except the last one :

\.(?=[^.]*\.)

Using a lookahead to check that's there another dot after the one we found (the lookahead's not part of the match).

Regex101

answered Mar 09 '23 at 16:43

SelVazi

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score 1 · Answer 2 · answered Mar 09 '23 at 16:43

1

Not sure if this is what you wanted. https://regex101.com/r/3FpEbq/1

Also in such situation you could replace first all the "." to "/", and then replace "/yaml$" to ".yaml"

answered Mar 09 '23 at 16:43

zolo

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score 1 · Answer 3 · answered Mar 09 '23 at 16:43

1

You need negative lookahead (see https://www.rexegg.com/regex-lookarounds.html):

\.(?!yaml)

Example: https://regex101.com/r/OdbsUb/1

answered Mar 09 '23 at 16:43

j.holetzeck

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score 1 · Answer 4 · answered Mar 09 '23 at 19:22

1

Generalized expression (means without "yaml" im regex):

positive lookahead like @SelVazi, or negative lookahead below:

(?!\.[^.]*$)\.

Look at https://regex101.com/r/lcd0ds/1 and https://www.pcre.org/pcre.txt

answered Mar 09 '23 at 19:22

msegit

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score 0 · Answer 5 · answered Mar 13 '23 at 16:59

First thanks to all of you.

But it doesnt work and it wont work. https://github.com/hashicorp/terraform/issues/28846

So i endend doing something like this, which TBH is a piece of crap...but...it opens another question which i will open here because i am again...lost.

> regex("/([^/]+)/?$", "fgdfsdf/sfsdfsdfsd/dsfsdfsdfs/gff0fff-fff-ff-dsfssd-cscsd.yaml")
[
  "gff0fff-fff-ff-dsfssd-cscsd.yaml",

and wrap it into this horrible oneliner

[for k, v in nonsensitive(data.sops_file.account_secrets.data) : "path=${regex("/([^/]+)/?$", replace(replace(k, ".", "/"), "/yaml", ".yaml"))} | data = ${v}"]

Yes, this is for importing all secrets from a SOPS file, to vault using several foreach.

Regex for extractig dots

5 Answers5