adding numbers two at a time in a list (python)

Question

list1=[1,2,3,4,5,6]
for x in range(len(list1)):
 print("{}+{}".format(list1[x],list1[x+1]))
 print(list1[x]+list1[x+1])

this is giving me 1+2=3, 2+3=5, 3+4=7, 4+5=9, 5+6=11. what I want as an out put is : 1+2=3, 3+4=7, 5+6=11

The third argument to `range` is a step which decides how much `x` gets incremented by each loop. — Carcigenicate, Mar 12 '23 at 14:13
Exactly the same problem: [how to print values from a python list in pairs without printing already printed index values](https://stackoverflow.com/questions/75673423/how-to-print-values-from-a-python-list-in-pairs-without-printing-already-printed) — Matthias, Mar 12 '23 at 15:01

Michael M. · Answer 1 · 2023-03-12T15:25:53.540

0

What you want to do is go through the list in pairs, so change the step argument of range() to 2:

list1=[1,2,3,4,5,6]
for x in range(0, len(list1)-1, 2):
  print("{}+{}".format(list1[x],list1[x+1]))
  print(list1[x]+list1[x+1])

edited Mar 12 '23 at 15:25

answered Mar 12 '23 at 14:14

Michael M.

2

You can also make the print statement more readable by using: print(f"{list[x]}+{list[x+1]} = {list[x] + list[x+1]}") instead of using format – Peter Burkert Mar 12 '23 at 14:16

score 0 · Accepted Answer · answered Mar 12 '23 at 14:26

0

list1=[1,2,3,4,5,6]
for x in range(0,len(list1)-1,2):
    print("{}+{}={}".format(list1[x],list1[x+1],(list1[x]+list1[x+1])))

OUTPUT

1+2=3

3+4=7

5+6=11

answered Mar 12 '23 at 14:26

2 Answers2