Regex missing number in group

Question

I'm using regex to split a string with a specific format but I'm still missing one number.

The string format is like this: "22TKL;33TKL;22FBL;35TKL". I'd like to receive as output pairs containing number and substrings like: (22, TKL), (33, TKL), (22, FBL), (35, TKL).

Using regex101 to create the expression, I came up with this: "[^;]+([0-9]+)([a-zA-z]+)". And according to regex101, the grouping is like this:

So, I'm unable to match the first number and don't know how to solve this.

Why not just split the string on semi-colons and extract the last 3 characters ? `[ (part[:-3],part[-3:]) for part in string.split(";") ]` — Alain T., Mar 14 '23 at 20:10

Ron Serruya · Accepted Answer · 2023-03-15T08:19:12.030

1

Just ([0-9]+)([a-zA-z]+) works fine https://regex101.com/r/sMxFQX/2

It didnt work for you since [^;]+ consumed the number, cause the number is a charcter thats not ;

Alternatively, if you do need this check, you can use this [^;]*?([0-9]+)([a-zA-z]+)

The ? I added makes it a lazy quantifier, meaning it consumes as few characters as it can, thus not matching the first digit if it doesn't have to

edited Mar 15 '23 at 08:19

answered Mar 14 '23 at 19:58

Ron Serruya

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You should explain the role of the question mark in your last line. – Cary Swoveland Mar 14 '23 at 20:03

JNevill · Answer 2 · 2023-03-14T20:12:14.273

If you are looking to get a list of lists as output to maintain the separation of the semicolons, you could consider splitting first by the semi-colon, and then throwing regex at each element:

list_of_lists = [re.findall(r'\d+|\D+', x) for x in  "22TKL;33TKL;22FBL;35TKL".split(";")]


[['22', 'TKL'], ['33', 'TKL'], ['22', 'FBL'], ['35', 'TKL']]

This keeps the regex nice and simple and gives you more workable output since the terms are maintained in their own list. This just says to look for either a set of numbers or a set of a non-numerics.

Regex missing number in group

2 Answers2