async await from callback function

Question

I have this function which saves user in database:

exports.saveUser = ({ first_name, last_name, email, password }) => {
    const query = "insert into users (first_name, last_name, email, password_hash) values ($1, $2, $3, $4) RETURNING *";
    bcrypt.hash(password, 10, async function (err, hash) {
        const res = await db.query(query, [first_name, last_name, email, hash]);
        return res.rows[0];
    });
    return res;
};

I have async function inside bcrypt callback where insertion is happening and where I'm returning inserted row. How do i make it to return for saveUser function?

So at the end saveUser() will be that res.rows[0] record?

saveUser() needs to be an async function so the caller can await it. — digby280, Mar 19 '23 at 17:48
"*I have async function inside bcrypt callback*" - don't do that. Get a promise for the result of the bcrypt call, wait for that. — Bergi, Mar 19 '23 at 18:16

Gia Nebieridze · Answer 1 · 2023-03-19T18:18:50.930

1

exports.saveUser = async ({ first_name, last_name, email, password }) => {
    const query = "insert into users (first_name, last_name, email, password_hash) values ($1, $2, $3, $4) RETURNING *";
    let hash = await bcrypt.hash(password, 10);
    const res = await db.query(query, [first_name, last_name, email, hash]);
    return res.rows[0];
};

i have made bcrypt.hash await instead of callback. then made saveUser async ad it worked

edited Mar 19 '23 at 18:18

answered Mar 19 '23 at 17:51

Gia Nebieridze

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Could you add a description on how this answers the question? (+1) – trincot Mar 19 '23 at 17:53

async await from callback function

1 Answers1