C nested char array change in function with pointers

Question

I have a array and ı want to change with pointers but array is nested char array like char array[][] how can i change the array in function.

char MAP[ROW][COLUMN] = {
    "00000000000000000000",
    "0                  0",
    "0                  0",
    "0                  0",
    "0                  0",
    "0                  0",
    "0                  0",
    "0                  0",
    "0                  0",
    "00000000000000000000",
};

for (int y = 0; y < ROW; y++)
{
    for (int x = 0; x< COLUMN; x++)
    {
        if (MAP[y][x] != '0')
        {
            MAP[y][x] = ' ';
        }
    }
}

I want the change this array in function.

First of all you need to pass the array to the function. Then you just use it as normal. — Some programmer dude, Mar 22 '23 at 18:04

score 0 · Accepted Answer · answered Mar 22 '23 at 18:07

You can declare the function either like

void change( char MAP[][COLUMN], int row )
{
    for (int y = 0; y < row; y++)
    {
        for (int x = 0; x< COLUMN; x++)
        {
            if (MAP[y][x] != '0')
            {
                MAP[y][x] = ' ';
            }
        }
    }
}

and call it like

change( MAP, ROW );

And in this case at least the identifier COLUMN must be defined before the function declaration.

Or if your compiler supports variable length array when

void change( int row, int column, char MAP[][column] )
{
    for (int y = 0; y < row; y++)
    {
        for (int x = 0; x< column; x++)
        {
            if (MAP[y][x] != '0')
            {
                MAP[y][x] = ' ';
            }
        }
    }
}

and call it like

change( ROW, COLUMN, MAP );

C nested char array change in function with pointers

1 Answers1