Python skipping pop

Question

I'm brand new to python, and trying to use it to sort through a .csv file. The file looks like below:

Date	Username	Full Name	Office	User Dept	Email	Card Num	Charged Acct	Shared Acct
4/20/2020 0:00	jdoe	Jane Doe	1	HR	jdoe@google.com	12345	USER
4/20/2020 0:00	jdoe	Jane Doe	1	HR	jdoe@google.com	12345	USER
4/20/2020 0:00	jdoe	Jane Doe	1	HR	jdoe@google.com	12345	USER
4/20/2020 0:00	jdoe	Jane Doe	1	HR	jdoe@google.com	12345	USER
4/20/2020 0:00	jdoe	Jane Doe	1	HR	jdoe@google.com	12345	USER
4/20/2020 0:00	jdoe	Jane Doe	1	HR	jdoe@google.com	12345	SHARED	ACCT1
4/20/2020 0:00	jdoe	Jane Doe	1	HR	jdoe@google.com	12345	SHARED	ACCT2
4/20/2020 0:00	jdoe	Jane Doe	1	HR	jdoe@google.com	12345	SHARED	ACCT3
4/20/2020 0:00	jdoe	Jane Doe	1	HR	jdoe@google.com	12345	SHARED	ACCT4
4/20/2020 0:00	jdoe	Jane Doe	1	HR	jdoe@google.com	12345	SHARED	ACCT5

My goal is to remove all rows where the Charged Acct column contains "USER". I'm first setting up a list like below, to export later into a .csv with all the user rows removed:

lines = list()

with open('C:/temp/pythonproject.csv', 'r') as readFile:
    reader = csv.reader(readFile)

    for row in reader:
        lines.append(row)

When I try to remove the rows with USER in the 8th column I'm using the below snippet and getting the below output where it only removes 3 of the instances and I can't for the life of me figure out why. Can anyone see anything wrong?

for row in lines:
    if row[7] == 'USER':
        lines.remove(row)
for row in lines:
    print(row[7])

Output:

Charged Acct
USER
USER
SHARED
SHARED
SHARED
SHARED
SHARED