variable that stores current date XSLT

Question

I need to create a variable that stores the current date but I only need the four digit year. Here is my code I don't understand why it doesn't work. note: Ive already tried using number(substring(current-date())) and it doesn't work either, I tried different methods and I can't get it to work.

<xsl:variable name="currentYear" select="year-from-dateTime(current-dayTime())"/>

<xsl:value-of select="$currentYear - year"/>

Im not sure I use vs code and I just installed the XML extension — sansievar, Mar 29 '23 at 17:29
@sansievar Find out - see here how: https://stackoverflow.com/a/25245033/3016153 — michael.hor257k, Mar 29 '23 at 17:33
XSLT 1.0 does not provide any standard way to get the current date/time. You could try passing in the current year as a parameter to your transformation from whichever environment you are calling it. — Sebastien, Mar 29 '23 at 17:48

score 0 · Answer 1 · answered Mar 29 '23 at 17:26

0

XSLT does not have a current-dayTime() function.

If your processor supports XSLT 2.0 or higher, you can use year-from-dateTime(current-dateTime()).

answered Mar 29 '23 at 17:26

y.arazim

866
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Just tried it and it doesnt work – sansievar Mar 29 '23 at 17:30

variable that stores current date XSLT

1 Answers1