how to get name of variable in console.log
code1 = 3;
code2 = 1;
code3 = 2;
console.log(Math.min(code1, code2, code3))
result is 1 but want also to print in console.log as : code2 =1
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Knowledge Seeker
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2You probably want to use an object... – epascarello Apr 04 '23 at 21:45
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Do you just want this for debugging or something else? – epascarello Apr 04 '23 at 21:45
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2It's never going to print code2. It's going to print the return value of Math.min(). – jarmod Apr 04 '23 at 21:47
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Hard to understand how you expect your code to do that... – Ruan Mendes Apr 04 '23 at 21:55
2 Answers
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const codeValues = {
code1: 3,
code2: 1,
code3: 2,
};
const minValue = Math.min(codeValues.code1, codeValues.code2, codeValues.code3);
const minCodeName = Object.keys(codeValues).find(key => codeValues[key] === minValue);
console.log(`${minCodeName} = ${minValue}`);
Ketan Rajpal
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Depends on what you mean but that - a question with what you tried and expected output would suffice – Mark Schultheiss Apr 04 '23 at 22:10
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You can use it like this
const nums=[3,1,2]
const minIndex= nums.indexOf(Math.min(...nums)),
codeName= `code${minIndex+1}`
console.log(`${codeName} = ${nums[minIndex]}`)
mkya
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