I am very new to programming and the computer world in general. I am trying to send a request to www.youtube.com using the requests module. When I type its address in my browser, everything works just fine and I can access YouTube without any problems. However, when I try to access YouTube with the following Python code:
import requests
requests.get("https://www.youtube.com")
I encounter the following errors:
Traceback (most recent call last):
File "C:\Users\BeBit\AppData\Local\Programs\Python\Python39\lib\site-packages\urllib3\connectionpool.py", line 700, in urlopen
self._prepare_proxy(conn)
File "C:\Users\BeBit\AppData\Local\Programs\Python\Python39\lib\site-packages\urllib3\connectionpool.py", line 996, in _prepare_proxy
conn.connect()
File "C:\Users\BeBit\AppData\Local\Programs\Python\Python39\lib\site-packages\urllib3\connection.py", line 369, in connect
self.sock = conn = self._connect_tls_proxy(hostname, conn)
File "C:\Users\BeBit\AppData\Local\Programs\Python\Python39\lib\site-packages\urllib3\connection.py", line 504, in _connect_tls_proxy
socket = ssl_wrap_socket(
File "C:\Users\BeBit\AppData\Local\Programs\Python\Python39\lib\site-packages\urllib3\util\ssl_.py", line 453, in ssl_wrap_socket
ssl_sock = _ssl_wrap_socket_impl(sock, context, tls_in_tls)
File "C:\Users\BeBit\AppData\Local\Programs\Python\Python39\lib\site-packages\urllib3\util\ssl_.py", line 495, in _ssl_wrap_socket_impl
return ssl_context.wrap_socket(sock)
File "C:\Users\BeBit\AppData\Local\Programs\Python\Python39\lib\ssl.py", line 500, in wrap_socket
return self.sslsocket_class._create(
File "C:\Users\BeBit\AppData\Local\Programs\Python\Python39\lib\ssl.py", line 1040, in _create self.do_handshake()
File "C:\Users\BeBit\AppData\Local\Programs\Python\Python39\lib\ssl.py", line 1309, in do_handshake
self._sslobj.do_handshake()
ssl.SSLEOFError: EOF occurred in violation of protocol (_ssl.c:1129)
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "C:\Users\BeBit\AppData\Local\Programs\Python\Python39\lib\site-packages\requests\adapters.py", line 489, in send
resp = conn.urlopen(
File "C:\Users\BeBit\AppData\Local\Programs\Python\Python39\lib\site-packages\urllib3\connectionpool.py", line 787, in urlopen
retries = retries.increment(
File "C:\Users\BeBit\AppData\Local\Programs\Python\Python39\lib\site-packages\urllib3\util\retry.py", line 592, in increment
raise MaxRetryError(_pool, url, error or ResponseError(cause))
urllib3.exceptions.MaxRetryError: HTTPSConnectionPool(host='www.youtube.com', port=443): Max retries exceeded with url: / (Caused by SSLError(SSLEOFError(8, 'EOF occurred in violation of protocol (_ssl.c:1129)')))
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "c:\Users\BeBit\Desktop\Python WorkPlace\MyProjectsandOnlyMines\YouTubeDownload.py", line 7, in <module>
requests.get("https://www.youtube.com")
File "C:\Users\BeBit\AppData\Local\Programs\Python\Python39\lib\site-packages\requests\api.py", line 73, in get
return request("get", url, params=params, **kwargs)
File "C:\Users\BeBit\AppData\Local\Programs\Python\Python39\lib\site-packages\requests\api.py", line 59, in request
return session.request(method=method, url=url, **kwargs)
File "C:\Users\BeBit\AppData\Local\Programs\Python\Python39\lib\site-packages\requests\sessions.py", line 587, in request
resp = self.send(prep, **send_kwargs)
File "C:\Users\BeBit\AppData\Local\Programs\Python\Python39\lib\site-packages\requests\sessions.py", line 701, in send
r = adapter.send(request, **kwargs)
File "C:\Users\BeBit\AppData\Local\Programs\Python\Python39\lib\site-packages\requests\adapters.py", line 563, in send
raise SSLError(e, request=request)
requests.exceptions.SSLError: HTTPSConnectionPool(host='www.youtube.com', port=443): Max retries exceeded with url: / (Caused by SSLError(SSLEOFError(8, 'EOF occurred in violation of protocol
(_ssl.c:1129)')))
I'm using a vless configuration in v2rayN if this information can help. can someone tell me what should I do?
"I expected to get <Response [200]> but I encountered a lot of errors."