6

Making an argument parser. I want to split a string into an array where the delimiter is ", " except when preceded by "|". That means string

"foo, ba|, r, arg"

should result in

`["foo", "ba|, r", "arg"]`

I'm trying to use this regex: (?<!\|), which works in http://regexhero.net/tester/ but when I try

args.split(/(?<!\|), /)

in ruby, I get an error: undefined (?...) sequence: /(?<!\|), /

tybro0103
  • 48,327
  • 33
  • 144
  • 170

1 Answers1

10

Ruby's regex engine doesn't support lookbehind (yet).

You'd need to switch to 1.9 or use Oniguruma.


If that's not an option, you can search for |, and replace it with some sort of marker. After all is said and done, put the |, back.

You can also try a regex like:

/(?:[^|]), /

But obviously the (?:[^|]) is not zero-width, which means you'll need to do some extra work afterwards.

NullUserException
  • 83,810
  • 28
  • 209
  • 234
  • note that Ruby now supports negative lookbehind at least as of 1.9.3: http://ruby-doc.org/core-1.9.3/Regexp.html – filsa Dec 05 '14 at 06:20