My question is that why python giving the ans is 7 without having the string in the count method
txt = "banana"
x = txt.count("")
print(x)
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001
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6https://docs.python.org/3/library/stdtypes.html#str.count – 001 May 01 '23 at 14:57
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1Read the [docs](https://docs.python.org/3/library/stdtypes.html#str.count). – Michael Butscher May 01 '23 at 14:57
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Actually, the string is there! It's kind of treated like `"-b-a-n-a-n-a-".count("-")` in this case. – TheCoder - or rather ACoder May 01 '23 at 14:59
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the empty string which you have used is basically the substring of every string and the `count()` method returns the substring's occurrences. – Pravash Panigrahi May 01 '23 at 15:00
2 Answers
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It can be fix by passing ' ' instead of '':
>>> 'banana'.count()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: count() takes at least 1 argument (0 given)
>>> 'banana'.count('')
7
>>> len('banana' ) + len('!')
7
>>> 'banana'.count( ' ')
0
>>> 'banana'.swapcase().count('B')
1
Explained
Q: Why it's printing the 7?
A: The len of an input string ("bnanana" == 6) + one extra character (1) --> total: 7
rv.kvetch
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@LiorV I added an explani section, so now it is more relevant. thanks! – rv.kvetch May 01 '23 at 15:13