Find recurring element from list

Question

list=['A', 'R', 'I','J','I','T','T']

def reccuring():
    count=0
    list1=[]
    for i in list:
        if list.count(i)>1:
            list1.append(i)
    return list1
reccuring()

OutPut

['I', 'I', 'T', 'T']

I am getting the recurring elements as many times as present in the list. What modification do I have to do to get the recurring elements only once?

Thank You

score 0 · Accepted Answer · answered May 07 '23 at 17:00

0

Better name your variables and use a set

values = ['A', 'R', 'I', 'J', 'I', 'T', 'T']

def reccuring():
    count = 0
    result = set()
    for value in values:
        if value not in result and values.count(value) > 1:
            result.add(value)
    return result

reccuring()

answered May 07 '23 at 17:00

azro

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may I please know why the list doesn't return only the element that is recurring? – user20666007 May 07 '23 at 17:10
@user20666007 what is your expected result ? – azro May 07 '23 at 17:37
I want 'I', 'J' – user20666007 May 08 '23 at 20:05
I mean 'I' and 'T'. Only the recurring letters. – user20666007 May 09 '23 at 04:33
@user20666007 the outout is `{'I', 'T'}` I don't understand what is the problem ? – azro May 09 '23 at 07:11

Find recurring element from list

1 Answers1