format function name as string and then call it? fn_call = f"static_{dynamic}" then fn_call()

Asked May 18 '23 at 19:50

Active May 18 '23 at 20:28

Viewed 28 times

I have a series of functions that do some data cleaning.

def clean_field_1(field_1): 
    return field_1

for example.

When looping through a dict of fields, field_1 may not be there. But if it is I'd like to call clean_field_1().

for field in dict_object:
    fn_call = f"clean_{field}"
    fn_call(field)

That's to illustrate the goal. In this case that final line errors because the str object is not callable.

Or it's possible that my approach is totally off base and I need a different one. Thanks for any pointers.

edited May 18 '23 at 19:52

wjandrea

asked May 18 '23 at 19:50

sam

Would `exec` work? https://www.geeksforgeeks.org/exec-in-python/ – TheTridentGuy supports Ukraine May 18 '23 at 19:54
2

Untested `locals.get(fn_call, globals.get(fn_call))(field)` – Steven Rumbalski May 18 '23 at 19:54
Or if your functions are in a different module `getattr(your_module, fn_call)(field)` – Steven Rumbalski May 18 '23 at 19:59
1

I didn't find links in the Question Closed notice helpful but I found this: https://stackoverflow.com/questions/4246000/how-to-call-python-functions-dynamically – sam May 18 '23 at 20:00

0 Answers0