sed command to match a pattern and replace it

Question

I want to use sed command to replace sensitive information in logs with ****. One of the log looks like:

"Log: abcservice : dataUsername generated is = QWE000387769@as.bbi.co\n","stream":"stdout""

The expected output I want is:

"Log: abcservice : dataUsername generated is = ******@as.bbi.co\n","stream":"stdout""

I tried:

sed 's#"dataUsername generated is [a-zA-ZO-9@.-]"#"dataUsername generated is = ******"#g"

How can I match the pattern "dataUsername generated is = QWE000387769@as.bbi.co" and replace it with "dataUsername generated is = ******@as.bbi.co\n"

I this really a programming question and not rather a general computing question about Linux? — tacoshy, May 23 '23 at 06:57

score 0 · Accepted Answer · answered May 23 '23 at 07:01

0

Using sed

$ sed -E 's/(dataUsername generated is = )[^@]*/\1******/' input_file
"Log: abcservice : dataUsername generated is = ******@as.bbi.co\n","stream":"stdout""

answered May 23 '23 at 07:01

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sed command to match a pattern and replace it

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