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How can i query distinct 'task_id'?

SELECT * 
FROM (SELECT tags.priority AS priority,  
             `dbbace69-6968-4b4d-9ac4-bcd8394beeab_tasks`.id, 
             RANK() OVER (ORDER BY tags.priority DESC) AS 'rank', 
             `dbbace69-6968-4b4d-9ac4-bcd8394beeab_tasks`.id AS task_id 
      FROM `dbbace69-6968-4b4d-9ac4-bcd8394beeab_tasks` 
      LEFT JOIN `dbbace69-6968-4b4d-9ac4-bcd8394beeab_task_tag` ON `task_id` = `dbbace69-6968-4b4d-9ac4-bcd8394beeab_tasks`.id 
      LEFT JOIN `tags` ON `dbbace69-6968-4b4d-9ac4-bcd8394beeab_task_tag`.`tag_id` = `tags`.`id` 
      WHERE `project_stage_id` = 'b30896ef-5737-4eeb-a988-346103ec2e80'  
            AND `dbbace69-6968-4b4d-9ac4-bcd8394beeab_tasks`.`deleted_at` IS NULL) AS subquery 
ORDER BY 'rank'
nacho
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0 Answers0