PEP 3107 annotation for a generator function

Question

simple question : What is the correct PEP 3107 keyword for a function that yields items ?

Already tried this, but it doesn't work

def this_function() -> generator:
    for x in range(0,100):
        yield x

Also tried with Iterator[int] as this post suggests, but no results. Also tried the various propositions made here, but nothing

N.B. Don't know if this is relevant, but my linter is Pylance on VSCode

`Iterator[int]` should have been fine. What error did you get? — chepner, Jun 05 '23 at 14:34
It's not in the built-in scope; you have to import it from `collections.abc`. — chepner, Jun 06 '23 at 12:37

Jab · Answer 1 · 2023-06-05T15:41:21.573

0

from collections.abc import Generator

def this_function() -> Generator[int, None, None]:
    for x in range(0, 100):
        yield x

from collections.abc import Iterable

def this_function() -> Iterable[int]:
    for x in range(0, 100):
        yield x

edited Jun 05 '23 at 15:41

answered Jun 05 '23 at 14:09

Jab

Note that the documentation also sanctions the use of `Iterator[X]` or `Iterable[X]` in place of `Generator[X, None, None]`. – chepner Jun 05 '23 at 14:32
(Also, `typing.Generator` is deprecated in favor of `collections.abc.Generator`. `typing` versions of various collections were only needed because the abstract classes weren't generic until Python 3.9.) – chepner Jun 05 '23 at 14:33
Thank you @chepner I was definitely behind the times. – Jab Jun 05 '23 at 15:36

1 Answers1