Java number format - #.## - Windows and Linux

Question

I'm using following code to format Double number

DecimalFormat decimalFormat=new DecimalFormat("#.##");
decimalFormat.format(1.04)

but this gives

java.lang.NumberFormatException: For input string: "1,04"

in Linux - but in Windows 7 this works fine, how to correct this?

Are you sure that the exception is being generated by the call to `format`? It looks like a message that comes from trying to parse rather than format. — Ted Hopp, Oct 04 '11 at 04:01
This should not matter between Windows or Linux .. and 1.04 is a valid decimal value so that exception does not look correct — CoolBeans, Oct 04 '11 at 04:06
Double.valueOf(decimalFormat.format(1.04)); this gives the exception — Buddhi, Oct 04 '11 at 04:08
possible duplicate of [DecimalFormat and Double.valueOf()](http://stackoverflow.com/questions/2691018/decimalformat-and-double-valueof) — Bohemian, Oct 04 '11 at 05:10

score 4 · Answer 1 · edited May 23 '17 at 12:27

4

There seems to be a very similar question answered here ( DecimalFormat and Double.valueOf() ) about the java number format. Basically the diference you are experiencing may be related to the Locale Settings defined on Windows being different to the Linux one (for example: on Windows you configured it to a contry/language different then the linux one).

edited May 23 '17 at 12:27

Community

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answered Oct 04 '11 at 04:06

Gabriel Mazetto

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I don't know what distro you are using, but I will give you the Ubuntu wiki instructions that will probably be similar or the same you are using right now: https://help.ubuntu.com/community/Locale Make sure all locale related variables are correctly defined. But also take a look of the suggestion on the link, as it seems to be more likely to be a permanent fix) – Gabriel Mazetto Oct 04 '11 at 04:48
Are you using the same Locale in both W7 and Linux? – YMomb Oct 04 '11 at 05:38

Java number format - #.## - Windows and Linux

1 Answers1