String concatenation with string literal and non string literal

Question

I want to understand what the following declaration means:

constexpr auto type = u"bluetooth-opp-transfer-complete"_ns;

I know constexpr evaluates things at compile time, but what does u mean here? Also will _ns gets appended here? if yes then how cause _ns is not defined anywhere.

https://en.cppreference.com/w/cpp/language/string_literal – Marek R Jun 12 '23 at 11:21 — Marek R, Jun 12 '23 at 11:21

score 1 · Answer 1 · answered Jun 12 '23 at 11:09

1

The u makes it a UTF-16 string literal. For more options see cppreference, for example.

answered Jun 12 '23 at 11:09

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String concatenation with string literal and non string literal

1 Answers1