Beautiful Soup is not filtering values

Question

hii all here i have a code snippet in which i am using beautiful soup to parse value

soup = BeautifulSoup(self.content, 'html.parser')
count = 1
for assumptions in data_list:
    for rec in soup.findAll():
        if (assumptions.replace(' ', '') in rec.get_text().replace(' ', '') or (assumptions.replace(' ', '') == rec.get_text().replace(' ', ''))
            if assumptions in data_list:
                data_list.remove(assumptions)
                count += 1

Here in self.content field I am getting the HTML data,

data_list is a list of strings

I am searching those strings which are available in the data_list inside the HTML content which is partially working.

some strings that I am searching for are avaliable in HTMl content but still, I am unable to process those in the if condition.

What will be the if condition in which I can parse all the strings which are inside the data_list

Am I misreading, or are both conditions in the `or` the same? — Barmar, Jun 13 '23 at 15:50
No actually its not the same @Barmar.. if i have done `===` then it will be same.... Anyway if i remove the if statement also its skipped the value — Sidharth Panda, Jun 13 '23 at 16:57
Then can you please suggest me the condition.. because every time i parse its misses some strings.. — Sidharth Panda, Jun 13 '23 at 17:00
If two strings are equal, then one is also in the other. You don't need both conditions, `in` is enough. — Barmar, Jun 13 '23 at 17:59
As explained, the problem isn't the condition, it's because you're modifying the list while you loop over it. So it skips some elements. — Barmar, Jun 13 '23 at 18:00
`data_list = [assumptions for assumptions in data_list if assumptions.replace(' ', '') not in soup.get_text().replace(' ', '')]` — Barmar, Jun 13 '23 at 18:04
There's no need to loop over `findAll()` since the text of soup is the concatenation of the text of all its elements. — Barmar, Jun 13 '23 at 18:05

Beautiful Soup is not filtering values

0 Answers0