printf in bash does not output hole string and dose not do the replace

Asked Jun 23 '23 at 10:05

Active Jun 23 '23 at 15:51

Viewed 36 times

I have long string

MESSAGE='<style>body{font-family:Arial,sans-serif;margin:0;padding:20px}h1{color:#333}p{margin-bottom:10px}.points{margin-bottom:20px}.point{margin-bottom:10px;list-style-type:disc}</style><p>Bonjour,</p><p>La plateforme INTERACTIVE FACTORY %s va entrer en maintenance.</p><p>Changement(s) :</p><ul>%s<div class="points"></ul></div><p>Laplateforme sera indisponible durant l"opération.</p>'

I want the place holders "%s" to be replaced with two other vars

var1="TOTO"
var2='<li class="points">5.2</li><li class="points">foo=verify-full</li>'

I did this but it's not working

newvar=printf $MESSAGE $var1 $var2

output

<style>body{font-family:Arial,sans-serif;margin:0;padding:20px}h1{color:#333}p{margin-bottom:10px}.points{margin-bottom:20px}.point{margin-bottom:10px;list-style-type:disc}</style><p>Bonjour,</p><p>La

why it's not working and why I get such output ?

edited Jun 23 '23 at 13:07

asked Jun 23 '23 at 10:05

Ali

Check your script with shellcheck – KamilCuk Jun 23 '23 at 10:20
https://www.shellcheck.net/ – Inian Jun 23 '23 at 10:21
1

`printf -v newvar "$MESSAGE" "$var1" "$var2"` -- mind the quotes. Or `newvar=$(printf "$MESSAGE" "$var1" "$var2")` – Charles Duffy Jun 23 '23 at 15:51
@CharlesDuffy that's correct you want to put that as response ? – Ali Jun 24 '23 at 16:06
The question is already closed so answers can't be added -- but everything you need to come up with those lines yourself is given in the two linked duplicates. – Charles Duffy Jun 24 '23 at 16:25

printf in bash does not output hole string and dose not do the replace

0 Answers0