Variable replacement in bash Scirpt

Question

I have a script that runs through all the files in my local directory and finds key words in my terraform files. The issue I'm facing is that I'm unable to replace defined variables in the files. When I reference value to be replaced, it captures $variable as the reference instead. For example:

Repository_Name="test"

grep -rl '#{RepositoryName}#' --include *.tf |
  xargs gsed -i 's/#{RepositoryName}#/${Repository_Name}/g'

I've also tried removing the {} outside the variable like the example below and still no luck:

Repository_Name="test"

grep -rl '#{RepositoryName}#' --include *.tf |
  xargs gsed -i 's/#{RepositoryName}#/$Repository_Name/g'

The result I usually get is:

RepositoryName = "$Repository_Name"

or

RepositoryName = "${Repository_Name}"

score 0 · Answer 1 · answered Jul 07 '23 at 01:02

0

You need " for the variables to be evaluated

Repository_Name="test"

grep -rl '#{RepositoryName}#' --include *.tf | xargs gsed -i "s/#{RepositoryName}#/${Repository_Name}/g"

You may also need extra { if you want them in the file.

answered Jul 07 '23 at 01:02

Diego Torres Milano

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Would I need to include the -e flag ? – AnotherEngineer Jul 07 '23 at 01:34
To `gsed`? It's not required – Diego Torres Milano Jul 07 '23 at 01:36
I'm getting this error: gsed: -e expression #1, char 58: unknown option to `s' – AnotherEngineer Jul 07 '23 at 01:38
There are no 58 chars in your example, so you are running something different – Diego Torres Milano Jul 07 '23 at 03:43
this worked. - https://stackoverflow.com/a/9366940/14329701 - I think the issue here was the character i had in the tf files creating char issues with sed. – AnotherEngineer Jul 07 '23 at 12:10

score 0 · Answer 2 · answered Jul 07 '23 at 11:11

0

Actually sed is enough:

sed -i '/#{RepositoryName}#/'"s||$Repository_Name|g" *.tf

answered Jul 07 '23 at 11:11

Ivan

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score 0 · Answer 3 · edited Jul 15 '23 at 18:51

0

The solution to this issue

grep -rl '#{RepositoryName}#' --include *.tf |
  xargs gsed -i "s@#{RepositoryName}#@${Repository_Name}@g"

There were char complications with sed.

for reference

edited Jul 15 '23 at 18:51

Charles Duffy

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answered Jul 07 '23 at 12:12

AnotherEngineer

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Variable replacement in bash Scirpt

3 Answers3