Why is an integer returned when disjunction is used with Math.random()?

Question

I use Math.random() * 10 to get a number between 0 and 10. However, when I use that with disjunction (|), the returned value becomes an integer even though I do not use such methods as Math.floor().

let n = Math.random() * 10;
// n is very likely a decimal number.

let n = Math.random() * 10 | 20;
// n becomes an integer.

@JohnKugelman, my question came from this post: https://stackoverflow.com/a/11972692/21023788 — kchui, Jul 09 '23 at 12:05

score 1 · Accepted Answer · answered Jul 09 '23 at 03:02

1

| is the bitwise OR operator and when applied to numbers, it first converts both operands to 32-bit integers.

answered Jul 09 '23 at 03:02

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Why is an integer returned when disjunction is used with Math.random()?

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