How to get a value from a dictionary which might be None in python

Question

There is a dictionary object named my_dic.

my_dic = {'name': 'tom'}
print(f"The name is {my_dic.get('name')}")

In case my_dic is None, there will be an expected exception as 'NoneType' object has no attribute 'get'.

How to make one line code to get None in case my_dic is None, otherwise return by get().

Thanks.

Yay! Another homework question intended to see if the student has learned the basics of the Python language. — Kurtis Rader, Jul 18 '23 at 05:41
Thanks guys. This is not a homework question. I was looking for the shortest solution without lots of if else with None. Yet, I think Chris and wjandrea's first solution is the best atm. — user3759386, Jul 19 '23 at 09:05

score 1 · Answer 1 · edited Jul 18 '23 at 04:32

1

You might use a conditional expression to handle the case where my_dic is None.

>>> my_dic = None
>>> print(f"The name is {my_dic.get('name') if my_dic else None}")
The name is None
>>> print(f"The name is {None if my_dic is None else my_dic.get('name')}")
The name is None

edited Jul 18 '23 at 04:32

wjandrea

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answered Jul 18 '23 at 04:19

Chris

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score 1 · Answer 2 · answered Jul 18 '23 at 04:28

1

my_dic = {'name': 'tom'} # return name 
# my_dic = None # return None if my_dic is None
print(f"The name is {my_dic.get('name')}" if my_dic is not None else None)

answered Jul 18 '23 at 04:28

Mahammadhusain kadiwala

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How to get a value from a dictionary which might be None in python

2 Answers2