How to get decorator name and it's parameters use reflection in python?

Asked Jul 19 '23 at 14:52

Active Jul 20 '23 at 05:55

Viewed 44 times

A simple function like this:

@app.get(path="/")
def read_root():
    raise ArithmeticError("Divide by zero")

I want to get the decorator information outside the function, for example: its name is: 'get', and its parameters have path="/"

edited Jul 20 '23 at 05:55

asked Jul 19 '23 at 14:52

zhizunbao

1

Inside the wrapped function `read_root()`? – Captain Trojan Jul 19 '23 at 14:55
@CaptainTrojan outside – zhizunbao Jul 20 '23 at 05:48
@zhizunbao what exactly are you trying to do? What is your input? `read_root`? That would depend entirely on the decorator. This looks like flask? Please provide a complete example. – juanpa.arrivillaga Jul 20 '23 at 05:59
@juanpa.arrivillaga I just want to get a decrator list of function . – zhizunbao Jul 20 '23 at 07:26
you aren't answering my question. what would **would be the input?** – juanpa.arrivillaga Jul 20 '23 at 08:57
@juanpa.arrivillaga Actually, I just want to know which decorators a function used and what their parameters are. The code was just written offhand. According to the code I found online, it seems to require the use of two modules: ast and inspect.Thanks., – zhizunbao Jul 20 '23 at 12:47

0 Answers0