how do you do that, to be able to issue a newfile.txt

Question

how to output "print(urls)" into new file.txt

   with open("path\url_example.txt") as file:

        for line in file:
        urls = re.findall('https?://(?:[-\w.]|(?:%[\da-fA-F]{2}))+', line)
        print(urls)

Answer 1

Code:

input_file_path = "/home/home/filessssss/example.txt"

# Output file path
output_file_path = "file.txt"

with open(input_file_path) as file:
    with open(output_file_path, "w") as output_file:
        for line in file:
            urls = re.findall('https?://(?:[-\w.]|(?:%\da-fA-F{2}))+', line)
            for url in urls:
                output_file.write(url + "\n")