Determine if object property includes array value

Question

Given the following array

[60, 1456]

How can I determine which items in this object do not have a corresponding id to the numbers in the array?

[
  {id: 60, itemName: 'Main Location - Cleveland'},
  {id: 1453, itemName: 'Second Location - Cleveland'},
  {id: 1456, itemName: 'Third Location - New York'}
]

`filter()` and `includes()` ? Please show us your attempt.... — 0stone0, Jul 24 '23 at 15:01
Also, it's not 'which items in this object' but 'which objects in this array'. — 0stone0, Jul 24 '23 at 15:03
I don't have any attempts because I don't know how to do it. Thanks though. — noclist, Jul 24 '23 at 15:05
Does this answer your question? [How do I check if an array includes a value in JavaScript?](https://stackoverflow.com/questions/237104/how-do-i-check-if-an-array-includes-a-value-in-javascript) — 0stone0, Jul 24 '23 at 15:06
Why does the OP ask almost the same question on exactly the same subject as already 3 days before ... [_"Determine the difference between values in object and array"_](https://stackoverflow.com/questions/76738740/determine-the-difference-between-values-in-object-and-array) .., especially since the OP already did accept an answer there — Peter Seliger, Jul 25 '23 at 08:43

piyush s · Answer 1 · 2023-07-24T15:22:17.267

1

You can try combination of filter & includes or filter & find or filter indexOf

const a = [60, 1456];

const b = [
  {id: 60, itemName: 'Main Location - Cleveland'},
  {id: 1453, itemName: 'Second Location - Cleveland'},
  {id: 1456, itemName: 'Third Location - New York'}
];

const idExists = b.filter(ob => {
 // const includes = !a.includes(ob.id);
 const find = a.find(id => id !== ob.id);

  return find;
})

// Efficient approach

const mapOfIds = a.reduce(acc, id => {...acc, [id]: id}, {});
const idExists = b.filter(ob => !mapOfIds[ob.id]);

edited Jul 24 '23 at 15:22

answered Jul 24 '23 at 15:09

piyush s

19
2

Why is this upvoted? Calling `find` **for each** item in the array is incredibly inefficient.... – 0stone0 Jul 24 '23 at 15:11
With includes also we are internally iterating on array for each item & with indexOf as well – piyush s Jul 24 '23 at 15:17
Added efficient approach as well – piyush s Jul 24 '23 at 15:19

score 1 · Accepted Answer · answered Jul 24 '23 at 15:10

Use filter() combined with includes() to check if the id does not (!) exists in the ids array:

const ids = [60, 1456];
const data = [
  {id: 60, itemName: 'Main Location - Cleveland'},
  {id: 1453, itemName: 'Second Location - Cleveland'},
  {id: 1456, itemName: 'Third Location - New York'}
];

const res = data.filter(({ id }) => !ids.includes(id));
console.log(res);

Determine if object property includes array value

2 Answers2