Add 10 seconds to a Date

Question

How can I add 10 seconds to a JavaScript date object?

Something like this:

var timeObject = new Date()     
var seconds = timeObject.getSeconds() + 10;
timeObject = timeObject + seconds;

Answer 1

There's a setSeconds method as well:

var t = new Date();
t.setSeconds(t.getSeconds() + 10);

For a list of the other Date functions, you should check out MDN

---

setSeconds will correctly handle wrap-around cases:

var d;
d = new Date('2014-01-01 10:11:55');
alert(d.getMinutes() + ':' + d.getSeconds()); //11:55
d.setSeconds(d.getSeconds() + 10);
alert(d.getMinutes() + ':0' + d.getSeconds()); //12:05

Answer 2

let timeObject = new Date();
const milliseconds = 10 * 1000; // 10 seconds = 10000 milliseconds
timeObject = new Date(timeObject.getTime() + milliseconds);

Answer 3

Just for the performance maniacs among us.

getTime

var d = new Date('2014-01-01 10:11:55');
d = new Date(d.getTime() + 10000);

5,196,949 Ops/sec, fastest

---

setSeconds

var d = new Date('2014-01-01 10:11:55');
d.setSeconds(d.getSeconds() + 10);

2,936,604 Ops/sec, 43% slower

---

moment.js

var d = new moment('2014-01-01 10:11:55');
d = d.add(10, 'seconds');

22,549 Ops/sec, 100% slower

---

So maybe its the least human readable (not that bad) but the fastest way of going :)

jspref online tests

Answer 4

const timeObject = new Date(); 
timeObject = new Date(timeObject.getTime() + 1000 * 10);
console.log(timeObject);

Also please refer: How to add 30 minutes to a JavaScript Date object?

Answer 5

Try this

a = new Date();
a.setSeconds(a.getSeconds() + 10);

Answer 6

I have a couple of new variants

1. var t = new Date(Date.now() + 10000);
2. var t = new Date(+new Date() + 10000);

Answer 7

timeObject.setSeconds(timeObject.getSeconds() + 10)

Answer 8

The Date() object in javascript is not that smart really.

If you just focus on adding seconds it seems to handle things smoothly but if you try to add X number of seconds then add X number of minute and hours, etc, to the same Date object you end up in trouble. So I simply fell back to only using the setSeconds() method and converting my data into seconds (which worked fine).

If anyone can demonstrate adding time to a global Date() object using all the set methods and have the final time come out correctly I would like to see it but I get the sense that one set method is to be used at a time on a given Date() object and mixing them leads to a mess.

var vTime = new Date();

var iSecondsToAdd = ( iSeconds + (iMinutes * 60) + (iHours * 3600) + (iDays * 86400) );

vTime.setSeconds(iSecondsToAdd);

Here is some more documentation that may help:

Answer 9

1. you can use setSeconds method by getting seconds from today and just adding 10 seconds in it

   var today = new Date();
   today.setSeconds(today.getSeconds() + 10);
   

2. You can add 10 *1000 milliseconds to the new date:

   var today = new Date(); 
   today = new Date(today.getTime() + 1000*10);
   

3. You can use setTime:

   today.setTime(now.getTime() + 10000)
   

Answer 10

The .setSeconds revealed quite strange misbehavior for me under node.js, so I use:

dateAddSeconds(date, seconds){ 
    return new Date( Date.parse(date) + seconds*1000 );
}

Answer 11

Try this way.

Date.prototype.addSeconds = function(seconds) {
  var copiedDate = new Date(this.getTime());
  return new Date(copiedDate.getTime() + seconds * 1000);
}

Just call and assign new Date().addSeconds(10)

Answer 12

If you need to add 10 seconds to current time you can use:

const date = new Date();
date.setUTCSeconds(date.getUTCSeconds() + 10); // Change 10 to any number of seconds

Answer 13

Few years ago i've wrote a 'generic' date function:

function addToDate({time_unit, operator, offset_value }) {
        const date = new Date();
  operator = operator == "after" ? "+" : "-";
  switch (time_unit) {
    case "seconds":
        date.setSeconds(eval(`${date.getSeconds()} ${operator} ${offset_value}`));
    break;

    case "hours":
        date.setHours(eval(`${date.getHours()} ${operator} ${offset_value}`));
      break;

    case "minutes":
        date.setMinutes(eval(`${date.getMinutes()} ${operator} ${offset_value}`));

      break;
    case "days":
        date.setDate(eval(`${date.getDate()} ${operator} ${offset_value}`));
      break;

    case "months":
        date.setMonth(eval(`${date.getMonth()} ${operator} ${offset_value}`));

      break;
    case "years":
        date.setFullYear(eval(`${date.getFullYear()} ${operator} ${offset_value}`));
      break;
    default:
      break;
  }

  return date;
}

const new_date = addToDate({time_unit:'seconds','operator':'after','offset_value':10});

console.log(new_date.toISOString());