Please have a look at the following code:
#include <stdio.h>
void main(){
int i = 2;
i = i++;
printf("%d",i);
}
I expected the answer to be 3, but it comes out to be 2. Could someone please explain why?
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What compiler do you use? GCC and Clang warn about the code being UB. – HolyBlackCat Aug 14 '23 at 08:01
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4I'm always puzzled about why people write code like this. – paddy Aug 14 '23 at 08:02
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It's just a general code snippet I found online, and didn't seem to get the answer I expected – Aevo Aug 14 '23 at 08:03
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So, you saw this online with absolutely no context behind it? Like _"don't do this"_ or something? – paddy Aug 14 '23 at 08:07
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Nope, it was just a question asked on my college portal, apparently it's supposed to be 'tricky' or something idrk – Aevo Aug 14 '23 at 08:09
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Whas it provided in context of sequence points? Or of undefined behaviour? – Gerhardh Aug 14 '23 at 08:09
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@Gerhardh that explains it, thanks – Aevo Aug 14 '23 at 08:10
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It was just given as a normal question, no context behind it. The question simply said tell us the output – Aevo Aug 14 '23 at 08:10
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Explain why you have this `i = i++;`? Is it experiment or you think it is good trick? – i486 Aug 14 '23 at 08:26
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There should be a special punishment for teachers showing code that has no use whatsoever! Even if it did work, it would still not be useful for anything. – BoP Aug 14 '23 at 10:26