How to convert ASCII code (0-255) to its corresponding character?

Question

How can I convert, in Java, the ASCII code (which is an integer from [0, 255] range) to its corresponding ASCII character?

For example:

65  -> "A"
102 -> "f"

this is not a duplicate as mentioned above. This is not conversion from integer but from char (ascii) — Chathuranga Chandrasekara, Oct 08 '11 at 00:32
*Not* a duplicate of "How to convert from int to String?"... anyway, FWIW, ASCII is only 7-bits with values [0, 127] ;-) — , Oct 08 '11 at 00:33
@phooji I think that that post sais how to convert 1->"1" etc' — Belgi, Oct 08 '11 at 00:35
@Belgi: Perhaps this is a better one: http://stackoverflow.com/questions/833709/converting-int-to-char-in-java . — phooji, Oct 08 '11 at 00:43
@Belgi - you'll need to explicitly state your encoding if you want to correctly transcode values 128-255. The term "extended ASCII" is not meaningful. — McDowell, Oct 08 '11 at 09:45

score 285 · Accepted Answer · edited Jun 05 '15 at 16:53

285

Character.toString ((char) i);

edited Jun 05 '15 at 16:53

thefourtheye

233,700
52
457
497

answered Oct 08 '11 at 00:28

Chathuranga Chandrasekara

20,548
30
97
138

For MIDP 2 / CLDC 1.1 based platforms (which don't have `Character.toString(char)`, http://stackoverflow.com/a/6210938/923560 provides additional solutions. – Abdull Sep 22 '14 at 12:07
What is the reason for the `(char)` designation? In other words, why can't I just put `Character.toString(i);` ? (Java noob) – Adam Hughes Oct 09 '15 at 14:19
1

Note that this will not work for the `Integer` type, you will get a "java.lang.Integer cannot be cast to java.lang.Character" error. Add a cast to `int` first, e.g.: `Character.toString((char)(int)myInteger);` – gbmhunter Jun 07 '16 at 04:00
1

The `i` values (0-255) would be from the ISO-8859-1 character set. (The question asker declined to identify which "extended ASCII" [vague term] was wanted, except by accepting this answer.) – Tom Blodget Nov 03 '17 at 13:30

score 67 · Answer 2 · answered Oct 08 '11 at 00:39

67

System.out.println((char)65); would print "A"

answered Oct 08 '11 at 00:39

RylandAlmanza

1,358
1
8
14

3

REPL tip: If you happen to be using JShell (Java 9) you can omit the System.out. Just type `(char) 65` to find out what character it is. – DavidS Jan 23 '18 at 23:55
3

Question is not about printing but converting. – iAmLearning Sep 11 '19 at 10:51

zjs · Answer 3 · 2011-10-08T00:49:00.840

38

String.valueOf(Character.toChars(int))

Assuming the integer is, as you say, between 0 and 255, you'll get an array with a single character back from Character.toChars, which will become a single-character string when passed to String.valueOf.

Using Character.toChars is preferable to methods involving a cast from int to char (i.e. (char) i) for a number of reasons, including that Character.toChars will throw an IllegalArgumentException if you fail to properly validate the integer while the cast will swallow the error (per the narrowing primitive conversions specification), potentially giving an output other than what you intended.

edited Oct 08 '11 at 00:49

answered Oct 08 '11 at 00:32

zjs

668
4
6

Assuming that the integer is in the range 0 to 255 (as you state that you do ... and as the question specifies), it is unnecessary and suboptimal to use `toChars`. – Stephen C Oct 08 '11 at 00:51
7

You're completely correct that something like `Character.toString((char) i)` is faster than `String.valueOf(Character.toChars(i))`. Running a quick benchmark of converting 1,000,000 random integers in the given range (100 times, to be safe) on my machine gives an average time of 153.07 nanoseconds vs. 862.39 nanoseconds. However, in any interesting application, there will be far more important things to optimize. The added value of the safe, deterministic handling and ease of expanding outside the [0,255] range should it be required outweighs the minor performance hit. – zjs Oct 08 '11 at 02:26

score 14 · Answer 4 · answered May 20 '15 at 22:24

14

int number = 65;
char c = (char)number;

it is a simple solution

answered May 20 '15 at 22:24

athena

279
3
11

score 7 · Answer 5 · edited Sep 04 '19 at 05:01

7

    new String(new char[] { 65 })

You will end up with a string of length one, whose single character has the (ASCII) code 65. In Java chars are numeric data types.

edited Sep 04 '19 at 05:01

wilmol

1,429
16
22

answered Oct 08 '11 at 00:33

Paul Cager

1,910
14
21

score 2 · Answer 6 · edited Dec 17 '14 at 14:59

2

An easier way of doing the same:

Type cast integer to character, let int n be the integer, then:

Char c=(char)n;
System.out.print(c)//char c will store the converted value.

edited Dec 17 '14 at 14:59

Uri Agassi

36,848
14
76
93

answered Dec 17 '14 at 14:56

Entriple Aardee

21
1

score 1 · Answer 7 · answered Jul 06 '14 at 03:09

1

One can iterate from a to z like this

int asciiForLowerA = 97;
int asciiForLowerZ = 122;
for(int asciiCode = asciiForLowerA; asciiCode <= asciiForLowerZ; asciiCode++){
    search(sCurrentLine, searchKey + Character.toString ((char) asciiCode));
}

answered Jul 06 '14 at 03:09

Tez Kurmala

89
5

score 1 · Answer 8 · answered Nov 02 '17 at 16:47

    for (int i = 0; i < 256; i++) {
        System.out.println(i + " -> " + (char) i);
    }

    char lowercase = 'f';
    int offset = (int) 'a' - (int) 'A';
    char uppercase = (char) ((int) lowercase - offset);
    System.out.println("The uppercase letter is " + uppercase);

    String numberString = JOptionPane.showInputDialog(null,
            "Enter an ASCII code:",
            "ASCII conversion", JOptionPane.QUESTION_MESSAGE);

    int code = (int) numberString.charAt(0);
    System.out.println("The character for ASCII code "
            + code + " is " + (char) code);

Explain your answer please – want2learn Nov 02 '17 at 16:57 — want2learn, Nov 02 '17 at 16:57

score -1 · Answer 9 · edited Oct 31 '16 at 20:49

-1

This is an example, which shows that by converting an int to char, one can determine the corresponding character to an ASCII code.

public class sample6
{
    public static void main(String... asf)
    {

        for(int i =0; i<256; i++)
        {
            System.out.println( i + ". " + (char)i);
        }
    }
}

edited Oct 31 '16 at 20:49

Lajos Arpad

64,414
37
100
175

answered Oct 31 '16 at 12:20

Prakash Hadgal

1

score -1 · Answer 10 · answered Nov 04 '16 at 01:16

-1

upper answer only near solving the Problem. heres your answer:

Integer.decode(Character.toString(char c));

answered Nov 04 '16 at 01:16

Maximilian Notar

21
2

How to convert ASCII code (0-255) to its corresponding character?

10 Answers10

Linked

Related